??j=0.39794 ??Y=0.21542 jj?Dj=354359.65 αc=1-??j=0.60206
项目 全厂汽水损失 锅炉排污 扩容蒸汽 浓缩排污水 化学补充水 小汽轮机用汽 锅炉蒸发量 再热蒸汽量 锅炉给水量 1-??jYj=0.78458 份额αx α1= 0.0101 αb1=DC=αc D0 =548497.48 流量Dx=α(kg/h) D1=9118.90 Db1=9118.90 Df=4803.22 D'b1=4315.68 Dma=13434.58 Dt=31130.67 Db=911980.55 Drh=770601.45 Dfw=921099.46 x0D/0.0101 αf= 0.00532 α'b1=0.00478 αma= 0.01488 αt=0.03448 αb= 1.0101 ααrh=fw= 1-α1-α2=0.85351 1.0202 1.5、汽轮机的功率校核 P1=
D(1h0?h1)?m?g3600D(2h0?h2)?m?g3600=4446.48kW
P2= =6723.80kW
P3=
D(3h0?h3?qrh)?m?g3600D(4h0?h4?qrh)?m?g3600 D(5h0?h5?qrh)?m?g3600D(6h0?h6?qrh)?m?g3600D(7h0?h7?qrh)?m?g3600D(8h0?h8?qrh)?m?g3600 =5199.94 kW
P4= =4675.85kW
P5= =9290.30 kW
P6= =7464.56kW
P7= =9002.40kW
P8= =10804.52 kW
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Pt=
D(th0?h4?qrh)?m?g3600 D(ch0?hc?qrh)?m?g3600 = 6528.31kW
Pc= =232293.71kW
汽轮机的总功率 Pe=(Pc+ Pt+计算误差
Δ=
?P)= 296429.87kW
jj=1?Pe?Pe,Pe?100%=1.19%
计算的电功率接近给定的电功率,说明计算结果准确。
1.6、热经济指标计算
1.6.1、汽轮机组热耗量(含小汽轮机)
Q0?D0(h0?hfw)?Drhqrh?Df(h''f?hfw)?Dma(hfw?hw)
=902861.65×(3395-1187.887)+770601.45×505+4803.22× (2773-1187.887)-13434.58×(1187.887-143.22) =2375450401 kJ/h
1.6.2、汽轮机组热耗率
q0=Q0/Pe=2375450401/300000=7918.17kJ/(kw·h)
1.6.3锅炉热负荷
Qb?Db(hb?hfw)?Drhqrh?Dbl(hbl?hfw)
× (3395-1187.887)+770601.45×505+9118.90×(1849.9-1187.887)
=2408034690kJ/h
1.6.4、各种效率
管道效率
ηp= Q0 /Qb=2375450401/2408034690=98.6%
机组热效率
ηe= 3600 /q0=3600/7918.17=45.47%
全厂热效率
ηcp=ηbηpηe=0.91?0.986?0.4547=40.8% 全厂热耗率
qcp= 3600 /ηcp =3600/0.408=8823.53kJ/(kw·h)
发电标准煤耗率
bcp =0.123/ηcp =0.1243/0.406=0.30147kg/(kw·h)
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2、疏水泵设置在8号低压加热器
在前面计算的基础上,直接从5号低压加热器计算以后的步骤。
2.1、各级加热器的计算 2.1.1、H5的计算
?5(h5- hs5) ?r= ?c4 (hw5-hw6)
?5(2926-434.45)×0.99=0.80678×(564.324-446.045) ?5h5 ?5=0.03869 2.1.2、H6的计算
hw5 ?5hs5 hw6 {?6(h6- hs6)+?5(hs5- hs6)} ?r= ?c4 (hw6-hw7) (2763-376.94)×0.99?6=0.80678×(433.04-363.46)-0.03869×(434.45-376.94)
?6=0.02282
?6h6 hw7hw6 ?5hs5 2.1.3、H7的计算
??5??6?hs6 {?7(h7- hs7)+(?5+?6)(hs6- hs7)} ?r=
(?c4-?5-?6-?7- ?8)(hw7-hw8)+ (?5+?6+?7+ a8)(hw7- hs8)
2257.3781 ?7-112.87 a8=87.5114147 ④
?7h7hw7 ??c4??5??6??7??8?hw8 ??5??6??7??8?hs8 ??5??6?hs6 ??5??6??7?hs7 2.1.4、H8的计算
{?8(h8- hs8)+ (?5+?6+ ?7)(hs7- hs8)}ηr=(?c4-?5-?6-?7)(hw8-hsg)
2616.025?8?380.416?7?182.613??hsg(0.745??7??8)
⑤
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hw8 ?8h8 ??c4??5??6??7??8?hsg ??5??6??7?hs7 ??c4??5??6??7??8?hsg 2.1.5、轴封加热器的计算 ?sg4(hsg4- hs)=(ɑc4-?5-?6-?7- ?8)(hsg- hc+1.7)- hsg(0.74527- ?7- ?8)
=-111.2620541-144.92 ?7-144.92 ?8 ⑥ 由④ ⑤ ⑥解得 ?7=0.03968
hsg ?sg4hsg4 ??c4??5??6??7??8?hc ?8=0.01829
2.1.6、凝气份额的计算
?sg4hs α
=1-α1-α2-α3-α4-α5-α6-α7-α8-αt-α
=0.61479
c
sg1-
α
sg2-
α
sg3-
α
sg4
2.2、汽轮机汽耗量及各段抽汽量计算 2.2.1、抽汽做功不足系数计算
根据已知参数,可以查水蒸汽表得到 hrh=3035 kJ/kg,hrh=3540 kJ/kg, 所以 qrh=3540-3035=505kJ/kg
h0-hc+qrh=(3395-2349+505)kJ/kg =1551 kJ/kg Y1=
in
outh1?hc?qrh=(3140-2349+505)/1551=0.8356
h0?hc?qrhh2?hc?qrh=(3035-2349+505)/1551=0.7679
h0?hc?qrhh3?hc=(3333-2349)/1551=0.6344
h0?hc?qrhY2=
Y3=
h4?hcY4= Yt==(3132-2349)/1551=0.5048
h0?hc?qrhY5=
h5?hc=(2926-2349)/1551=0.3720
h0?hc?qrhh6?hc=(2763-2349)/1551=0.2669
h0?hc?qrhY6=
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