运河数学网( http://yhsxw.vicp.net ) 2010中考真题 ∴C(1,23). ···························· 3分 ⑵①在Rt△ACE中,tan∠CAE=
CE?3, AE∴∠CAE=60o,
由抛物线的对称性可知l是线段AB的垂直平分线, ∴AC=BC,
∴△ABC为等边三角形, ···················································· 4分 ∴AB= BC =AC = 4,∠ABC=∠ACB= 60o, 又∵AM=AP,BN=BP, ∴BN = CM,
∴△ABN≌△BCM, ∴AN=BM. ········································································ 5分 ②四边形AMNB的面积有最小值. ········································ 6分 设AP=m,四边形AMNB的面积为S,
3由①可知AB= BC= 4,BN = CM=BP,S△ABC=×42=43,
4∴CM=BN= BP=4-m,CN=m, 过M作MF⊥BC,垂足为F,
3(4?m), 则MF=MC?sin60o=233211(4?m)=?m?3m, ∴S△CMN=CN?MF=m?···················· 7分 2422∴S=S△ABC-S△CMN
32m?3m) =43-(?4=3(m?2)2?33 ····························································· 8分 4∴m=2时,S取得最小值33. ·············································· 9分
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