C语言编程实例100题精编版

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y=ceil(y0+48+sin(a)*B); setcolor(2); line(x0,y0,x,y); }

for(j=1;j<=50;j++) {

a=(2*PAI/16)*i+(2*PAI/180)*k-1; x=ceil(x0+48*cos(a)); y=ceil(y0+48*sin(a)*B); line(x0,y0,x,y); } }

restorecrtmode(); }

============================================================== 【程序60】

题目：画图，综合例子。 1.程序分析： 2.程序源代码：

＃i nclude \#define LEFT 0 #define TOP 0

#define RIGHT 639 #define BOTTOM 479 #define LINES 400

#define MAXCOLOR 15 main() {

int driver,mode,error; int x1,y1; int x2,y2;

int dx1,dy1,dx2,dy2,i=1; int count=0; int color=0; driver=VGA; mode=VGAHI;

initgraph(&driver,&mode,\x1=x2=y1=y2=10; dx1=dy1=2; dx2=dy2=3; while(!kbhit()) {

line(x1,y1,x2,y2); x1+=dx1;y1+=dy1; x2+=dx2;y2+dy2;

if(x1<=LEFT||x1>=RIGHT) dx1=-dx1;

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if(y1<=TOP||y1>=BOTTOM) dy1=-dy1;

if(x2<=LEFT||x2>=RIGHT) dx2=-dx2;

if(y2<=TOP||y2>=BOTTOM) dy2=-dy2;

if(++count>LINES) {

setcolor(color);

color=(color>=MAXCOLOR)?0:++color; } }

closegraph(); }

【程序61】

题目：打印出杨辉三角形（要求打印出10行如下图） 1.程序分析： 1

1 1 1 2 1 1 3 3 1 1 4 6 4 1

1 5 10 10 5 1 2.程序源代码： main() {int i,j;

int a[10][10]; printf(\

for(i=0;i<10;i++) {a[i][0]=1; a[i][i]=1;} for(i=2;i<10;i++) for(j=1;j

a[i][j]=a[i-1][j-1]+a[i-1][j]; for(i=0;i<10;i++) {for(j=0;j<=i;j++) printf(\ printf(\ } }

============================================================== 【程序62】

题目：学习putpixel画点。

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1.程序分析： 2.程序源代码： ＃i nclude \＃i nclude \main() {

int i,j,driver=VGA,mode=VGAHI; initgraph(&driver,&mode,\setbkcolor(YELLOW); for(i=50;i<=230;i+=20) for(j=50;j<=230;j++) putpixel(i,j,1);

for(j=50;j<=230;j+=20) for(i=50;i<=230;i++) putpixel(i,j,1); }

============================================================== 【程序63】

题目：画椭圆ellipse 1.程序分析： 2.程序源代码： ＃i nclude \＃i nclude \＃i nclude \main() {

int x=360,y=160,driver=VGA,mode=VGAHI; int num=20,i; int top,bottom;

initgraph(&driver,&mode,\top=y-30; bottom=y-30;

for(i=0;i

ellipse(250,250,0,360,top,bottom); top-=5; bottom+=5; }

getch(); }

============================================================== 【程序64】

题目：利用ellipse and rectangle 画图。 1.程序分析： 2.程序源代码： ＃i nclude \

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＃i nclude \＃i nclude \main() {

int driver=VGA,mode=VGAHI; int i,num=15,top=50; int left=20,right=50;

initgraph(&driver,&mode,\for(i=0;i

ellipse(250,250,0,360,right,left); ellipse(250,250,0,360,20,top);

rectangle(20-2*i,20-2*i,10*(i+2),10*(i+2)); right+=5; left+=5; top+=10; }

getch(); }

============================================================== 【程序65】

题目：一个最优美的图案。 1.程序分析： 2.程序源代码：

＃i nclude \＃i nclude \＃i nclude \＃i nclude \＃i nclude \＃i nclude \＃i nclude \#define MAXPTS 15 #define PI 3.1415926 struct PTS { int x,y; };

double AspectRatio=0.85; void LineToDemo(void) {

struct viewporttype vp;

struct PTS points[MAXPTS]; int i, j, h, w, xcenter, ycenter; int radius, angle, step; double rads;

printf(\getviewsettings( &vp );

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h = vp.bottom - vp.top; w = vp.right - vp.left;

xcenter = w / 2; /* Determine the center of circle */ ycenter = h / 2; radius = (h - 30) / (AspectRatio * 2);

step = 360 / MAXPTS; /* Determine # of increments */ angle = 0; /* Begin at zero degrees */ for( i=0 ; i

circle( xcenter, ycenter, radius ); /* Draw bounding circle */ for( i=0 ; i

{int driver,mode;

driver=CGA;mode=CGAC0; initgraph(&driver,&mode,\setcolor(3);

setbkcolor(GREEN); LineToDemo();}

============================================================== 【程序66】

题目：输入3个数a,b,c，按大小顺序输出。 1.程序分析：利用指针方法。 2.程序源代码： /*pointer*/ main() {

int n1,n2,n3;

int *pointer1,*pointer2,*pointer3;

printf(\scanf(\pointer1=&n1; pointer2=&n2; pointer3=&n3;

if(n1>n2) swap(pointer1,pointer2); if(n1>n3) swap(pointer1,pointer3); if(n2>n3) swap(pointer2,pointer3);

printf(\}

swap(p1,p2) int *p1,*p2; {int p;

p=*p1;*p1=*p2;*p2=p; }

============================================================== 【程序67】

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