【答案】(1)??x?4?x?2??3??;(2)m??3或m?5. ???x?2,x??1?2【解析】(1)f?x??2x?1?x?1=??3x,?1?x?1, ?2??x?2,x?1??∴??x??1?2或????12?x?1或??x?1,解得?4?x??1或12??x?2?2??3x?2?x?2?22?2?x?3或无解,综上,不等式f?x??2的解集是??x?4?x?2??3??. (2)f?x??x?1?2x?3?2x?1?x?1?x?1?2x?3?2x?1?2x?3
?2x?1??2x?3??4,
当?12?x?32时等号成立不等式m?1?f?x??x?1?2x?3有解,
∴m?1???f?x??x?1?2x?3??min,
∴m?1?4,∴m?1??4或m?1?4,即m??3或m?5, ∴实数m的取值范围是m??3或.
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