?PS??33t?, 22E是AB中点,AD//EF,AB=2, AD?EN?PE
PA?EN?2(t?1)
t?QN?2t?2(t?1) …….…………………………(3分)
t?S?DPQ?1(2t?2(t?1))(2t=
333t??) 2223233t?t? 2223233t?t?………….…….…………………………(4分) 222S?(3)根据题意可知:AM?1t, 2?DM?2?1t
2?DP2?(DM)2?(PM)2
13DP2?(2?t)2?(t)2
22DP2?t2?2t?4
根据勾股定理可得:DQ?(2321)?(2t?2?)2 22DQ2?(321)?(2t?2?)2?4t2?10t?7 22t?123(t?1)2)?() 22PQ2?QN2?PN2?(2t?PQ2?7t2?4t?1
① 当?PDQ?90?
PQ2?DQ2?PD2
7t2?4t?1=4t2?10t?7+t2?2t?4
解之得:t?6?1(舍负)…….…………………………(5分)
222② 当?DPQ?90?DQ?PQ?PD
4t2?10t?7=7t2?4t?1+t2?2t?4
解之得:t?6?1(舍负)…….…….……………………(6分) 2222③ 当?DQP?90?,PD?DQ?PQ
t2?2t?4=7t2?4t?1+4t2?10t?7
解之得:t?4?6…….…….…………………………(7分) 54?66?1,t?6?1时?DPQ是直角三角形. ,t?52综上,当t?
[注]学生正确答案与本答案不同,请老师们酌情给分。
相关推荐: