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ºáÏòˮƽ¸Ë£ºRmax=1¡Á1.44kN¡ÜRc=0.85¡Á12=10.2kN ×ÝÏòˮƽ¸Ë£ºRmax=1¡Á3.327kN¡ÜRc=0.85¡Á12=10.2kN Âú×ãÒªÇó£¡
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Á¢¸ËÅźŠ1 2 3 4 5 Á¢¸Ë´îÉè¸ß¶ÈHs(m) 10.7 25 25 25 25 Ë«Á¢¸Ë¼ÆË㷽ʽ ²»ÉèÖÃË«Á¢¸Ë °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ Ë«Á¢¸Ë¼ÆËã¸ß¶Èh1(m) / 14 14 14 14 6 7 8 9 10 11 12 13 25 25 25 25 25 25 25 25 °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ °´Ë«Á¢¸ËÊÜÁ¦Éè¼Æ ÿÃ×Á¢¸Ë³ÐÊܽṹ×ÔÖØ±ê×¼Öµgk(kN/m) 14 14 14 14 14 14 14 14 Ë«Á¢¸Ë²»¾ùÔÈϵÊýK 0.6 0.129 Á¢¸Ë¾²ºÉÔØ¼ÆËã
1¡¢Á¢¸Ë³ÐÊܵĽṹ×ÔÖØ±ê×¼ÖµNG1k
Á¢¸ËÒ»:NG1k=(gk+lb¡Án/2¡Á0.04/h)¡ÁH=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á10.7=1.795kN Á¢¸Ë¶þ:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÈý:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËËÄ:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÎå:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÁù:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÆß:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸Ë°Ë:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸Ë¾Å:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÊ®:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸Ëʮһ:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÊ®¶þ:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN Á¢¸ËÊ®Èý:
µ¥Á¢¸ËNG1k=(gk+lb¡Án/2¡Á0.04/h)¡Á(H-h1)=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á(25-14)=1.845kN
Ë«Á¢¸ËNGs1k=(gk+lb¡Án/2¡Á0.04/h)¡Áh1=(0.129+1.2¡Á2/2¡Á0.04/1.23)¡Á14=2.348kN 2¡¢½ÅÊÖ°åµÄ×ÔÖØ±ê×¼ÖµNG2k1 Á¢¸Ë
Ò»:NG2k1=(H/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/2=(10.7/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/2=1.222kN Á¢¸Ë¶þ:
µ¥Á¢¸ËNG2k1=((H-h1)/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=((25-14)/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=2.506kN Ë«Á¢¸Ë
NGs2k1=(h1/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=(14/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=3.12kN Á¢¸ËÈý:
µ¥Á¢¸ËNG2k1=((H-h1)/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=((25-14)/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=2.506kN Ë«Á¢¸Ë
NGs2k1=(h1/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=(14/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=3.12kN Á¢¸ËËÄ:
µ¥Á¢¸ËNG2k1=((H-h1)/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=((25-14)/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=2.506kN Ë«Á¢¸Ë
NGs2k1=(h1/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=(14/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=3.12kN Á¢¸ËÎå:
µ¥Á¢¸ËNG2k1=((H-h1)/h+1)¡Ála¡Álb¡ÁGkjb¡Á1/2/1=((25-14)/1.23+1)¡Á1.2¡Á1.2¡Á0.35¡Á1/2/1=2.506kN
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