r = (listnode *) malloc (sizeof(listnode)); r ->con = (p ->con) / (p ->exp + 1 ); r ->exp =((p ->exp ) + 1); r ->next = operdy_head ->next ; operdy_head ->next = r; operdy_head ->exp ++; bubble_sort(operdy_head); bubble_sort(operdy_head); return operdy_head; }
int _tmain(int argc, _TCHAR* argv[]) { printf(\请依次输入第1个多项式的各个元素:(例: input(); printf(\请依次输入第2个多项式的各个元素:(例: input(); bubble_sort(point[0]); bubble_sort(point[1]); bubble_sort(point[0]); bubble_sort(point[1]); //整理顺序 printf(\第1个多项式为:\\n\ output(point [0]); printf(\第2个多项式为:\\n\ output(point [1]); printf(\多项式1+多项式2 =:\\n\ operplus(); output(head); printf(\多项式1-多项式2 =:\\n\ operminus(); output(head); printf(\多项式1*多项式2 =:\\n\ opermul(); output(head); printf(\多项式1关于x求导得:\\n\ head = operdy(head1); output(head); printf(\多项式2关于求导得:\\n\ head = operdy(head2); output(head); printf(\多项式1关于y的积分\\n\ head = operjifen(head1); output(head); printf(\多项式2关于y的积分\\n\ head = operjifen(head2); output(head); printf(\ getchar(); getchar(); return 0; }
-9x^3 应该输入 -9 3)\\n\-9x^3 应该输入 -9 3)\\n\
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