船舶静力学课后习题答案

Cb=V/(4r*2r*r)=π/12=0.261 Cvp=V/(4r*r)=π/6=0.522 4/4

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Exercise 1-3

某海洋客货轮排水体积V=9750m，长宽比L/B=8，宽 度吃水比B/d=2.63，船型系数Cm=0.9, Cp=0.66, Cvp= 0.78，试求：（1）船长L；（2）船宽B;（3）吃水d；（4）水线面系数Cw；（5）方形系数Cb；（6）水线面面积Aw。 解：Cp=V/CmBdL=V/CmB(B/2.63)(8B)=2.63V/8CmB ∴B=((9750*2.63)/(8*0.66*0.9))=17.54m

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L=8*17.54=140.32m d=17.54/2.63=6.67m

Cb=Cm.Cp=0.9*0.66=0.594 Cw=Cb/Cvp=0.594/0.78=0.762

Aw=0.762*140.32*175.54=1875.44m2

Exercise 1-4

已知某巡逻艇d=2.05m，L/B=6.7，B/d=2.46，Cb=0.53。求排水体积。

解：B=B/d*d=2.46*2.05=5.043 L=L/B*B=6.7*5.043=33.788

V=CbLBd=0.53*33.788*5.043*2.05=185.13 t

Exercise 1-5

V=25m3，L/B=5，B/d=2.7，Cb=0.52。求该艇

解：∵Cb=V/LBd=V/(5B*B*B/2.7) ∴B=((2.7*25)/(5*0.52))1/3

=2.96 m L=5*B=14.8 m d=B/2.7=2.96/2.7=1.10 m

已知某游艇的主尺度。

Exercise 1-6

某内河驳船的水下体积V=4400m3，吃水d=2.6m，方形系数Cb=0.815，水线面系数Cw=0.882，求水线面面积 Aw。

已知：Cb=0.815;Cw=0.882;V=4400t 解：Cvp=Cb/Cw=0.815/0.882=0.924 ∵Cvp=V/(Aw.d)

∴Aw=V/(Cvp.d)=4400/(0.924*2.6)=1831.5 m

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