c++-primer-plus（第六版）第二至第六章课后编程练习全部答案

snack[1].calory=400; snack[2].brand=\ snack[2].weight=4.4; snack[2].calory=500;

for(int i=0;i<3;i++) { cout << \ cout << \ cout << \ }

delete [] snack; return 0; }

//ex.4.10 数组—方法1 #include int main() {

using namespace std; const int Size = 3; int success[Size];

cout<<\ cin >> success[0]>>success[1]>>success[2]; cout<<\ cout<<\ cout<<\ double average=(success[0]+success[1]+success[2])/3; cout<<\ return 0; }

//ex.4.10 array—方法2 #include #include int main() {

using namespace std; arrayad={0};

cout<<\ cin >> ad[0]>>ad[1]>>ad[2];

cout<<\

cout<<\ cout<<\ ad[3]=(ad[0]+ad[1]+ad[2])/3; cout<<\ return 0; }

第五章 循环和关系表达式

//ex.5.1

#include

int main() {

using namespace std;

cout<<\ int num1,num2; cin>>num1>>num2; int sum=0;

for(int temp=num1;temp<=num2;++temp)//or temp++ sum+=temp;

cout<<\ return 0; }

//ex.5.2

#include #include

int main() {

using namespace std; }

arrayad={0}; for(int i=2;i<101;i++)

ad[i]=i*ad[i-1];

cout<

return 0;

//ex.5.3

#include int main() {

using namespace std;

cout<<\ int sum=0,num;

while((cin>>num)&&num!=0) {

sum+=num;

cout<<\ cout<<\ }

return 0; }

//ex.5.4

#include int main() {

using namespace std; double sum1,sum2; sum1=sum2=0.0; int year=0; while(sum2<=sum1) {

++year; sum1+=10;

sum2=(100+sum2)*0.05+sum2; }

cout<<\经过\年后，Cleo的投资价值才能超过Daphne的投资价值。\ cout<<\此时，Cleo的投资价值为\，而Daphne的投资价值为\ return 0; }

//ex.5.5

#include const int MONTHS = 12; const

ember\int main() {

using namespace std; int sales[MONTHS],sum=0; for(int i=0;i

cout<<\请输入在\的C++ For Fools的销售量：\ cin>>sales[i]; sum+=sales[i]; }

cout<<\这一年中的C++ For Fools的总销售量为：\ return 0; }

char*

months[MONTHS]={\

//ex.5.6

#include const int MONTHS = 12; const

ember\

const char* years[3]={\第一年\第二年\第三年\int main() {

using namespace std;

int year_sale[3],sum=0,sales[3][MONTHS]; for(int i=0;i<3;i++) {

int temp=0;

cout<

cout<<\请输入\的销售量:\ cin>>sales[i][j]; temp+=sales[i][j]; }

year_sale[i]=temp;

char*

months[MONTHS]={\