PB?平面PBG,?AD?PB
(3)由AD?PB,AD∥BC,?BC?PB 又BG?AD,AD∥BC,?BG?BC ??PBG为二面角A?BC?P的平面角
在Rt?PBG中,PG?BG,??PBG?45 12.证明:连结MO,A1M,∵DB⊥A1A,DB⊥AC,
0A1A?AC?A,
?平面A1ACC1 ∴DB⊥A1O. ∴DB⊥平面A1ACC1,而AO1设正方体棱长为a,则A1O?在Rt△A1C1M中,A1M?22323a,MO2?a2. 2492a.∵A1O2?MO2?A1M2,∴4AO?OM. 1∵OM∩DB=O,∴ A1O⊥平面MBD. .
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