临时用电专项施工方案(参考范本)

序号 机具名称 型号 安装功率(kW) 数量 合计功率(kW) 1 塔式起重机 QTZ80 31.5 3 94.5 2 施工升降机 SC200 33 3 37.5 3 木工平刨 MB1043 3 1 3 4 圆盘锯 MJ114 3 1 3 5 搅拌机 Jzc350 7.5 3 22.5 6 钢筋弯曲机 GJ5-8 5.5 2 11 7 钢筋切断机 GJ5-40 7.5 2 15 8 电焊机 BX300 25 1 25 9 对焊机 UNI-80 100 1 100 10 竖向焊机 SH-40 30 1 30 11 插入式振动器 HZ69-70A 3 3 9 12 平板式振动器 P2-50 3.5 2 7 13 蒸饭车 9 1 9 14 开水器 15 1 15 15 空调 1.5 55 82.5 2、确定用电负荷: (1)、塔式起重机

Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Jc =40% Pn = 31.5kW Pe = n×(Jc/Jc1)1/2×Pn =数量×(0.4/0.25)1/2×31.5 = 119.5kW Pjs = Kx×Pe =0.3×119.5 = 35.86 kW Qjs = Pjs× tgφ=35.86×1.02 = 36.58 kvar （2）施工升降机

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02 Pjs = Kx×∑Pe = 0.7×数量×33 = 46.2 kW Qjs = Pjs× tgφ=46.2×1.02 =47.12 kvar (3)、木工平刨

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02

Pjs = Kx×∑Pe = 0.7×数量×3 = 2.1kW Qjs = Pjs×tgφ=2.1×1.02 = 2.14 kvar (4)、圆盘锯

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02 Pjs = Kx×∑Pe = 0.7×数量×3 =2.1 kW Qjs = Pjs× tgφ=2.1×1.02 =2.14 kvar (5)、搅拌机

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02 Pjs = Kx×∑Pe = 0.7×数量×22.5= 15.75kW Qjs = Pjs× tgφ=15.75×1.02 =16.07kvar (6)、钢筋棚机械

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02

Pjs = Kx×∑Pe =0.7×（5.5×数量+7.5×数量）=18.2kW Qjs = Pjs× tgφ18.2×1.02 = 18.56kvar (7)、电焊机

Kx = 0.5 Cosφ = 0.45 tgφ = 1.984 将Jc =50%统一换算到Jc1 =100%的额定容量 Pn = Sn ×Cosφ = 11.25kW

Pe = n×(Jc/Jc1)1/2×Pn =数量×(0.5/1)1/2×11.25 = 7.95kW Pjs = Kx×Pe =0.5×7.95 = 3.98 kW Qjs = Pjs× tgφ=3.98×1.984 = 7.9kvar (8)、对焊机

Kx = 0.5 Cosφ = 0.45 tgφ = 1.984 将Jc =50%统一换算到Jc1 =100%的额定容量 Pn = Sn ×Cosφ = 45kW

Pe = 数量×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×45 =31.82kW Pjs = Kx×Pe =0.5×31.82 = 15.91 kW Qjs = Pjs× tgφ=15.91×1.984 = 31.56kvar

(9)、竖向焊机

Kx = 0.5 Cosφ = 0.45 tgφ = 1.984 将Jc =50%统一换算到Jc1 =100%的额定容量 Pn = Sn ×Cosφ = 13.5kW

Pe = n×(Jc/Jc1)1/2×Pn =数量×(0.5/1)1/2×13.5 =9.55kW Pjs = Kx×Pe =0.5×9.55 = 4.77 kW Qjs = Pjs× tgφ=4.77×1.984 = 9.47kvar (10)、泥工机械

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02

Pjs = Kx×∑Pe= 0.7×（3×数量+3.5×数量） =11.2kW Qjs = Pjs× tgφ=11.2×1.02 =11.42 kvar (11)、厨房设备

Kx = 0.7 Cosφ = 0.7 tgφ = 1.02 Pjs = Kx×∑Pe= 0.7×（9+15） =16.8kW Qjs = Pjs× tgφ=16.8×1.02 =17.14 kvar (12)、空调

因为空调是单相用电，三相平均分配取Pn=55/3（取整数）=19 Kx = 0.7 Cosφ = 0.7 tgφ = 1.02

Pjs = Kx×∑Pe= 0.7×（数量×1.5） =19.95kW Qjs = Pjs× tgφ=19.95×1.02 =20.35 kvar （13）、100m高扬程水泵

Kx = 0.75 Cosφ = 0.8 tgφ = 0.75 Pjs = Kx×∑Pe = 0.75×数量×20 = 15 kW Qjs = Pjs×tgφ=15×0.75 = 11.25 kvar

总的计算负荷计算，总箱同期系数取 Kx = 0.9，照明按照总功率的10%计 总的有功功率 Pjs = Kx×ΣPjs

= 0.9×1.1×

(35.86+26.25+2.1+2.1+15.75+18.2+3.98+15.91+4.77+11.2+16.8+19.95) = 172.87kW 总的无功功率 Qjs = Kx×ΣQjs =0.9×1.1×

(36.58+26.78+2.14+2.14+16.07+18.56+7.9+31.56+9.47+11.42+17.14+20.35) =200.11 kvar 总的视在功率

Sjs = ( Pjs2+Qjs2 )1/2 = (172.872+200.112)1/2 =264.44kVA 总的计算电流计算

Ijs = Sjs/(1.732×Ue) =264.44/(1.732×0.38) =401.78 A 据计算负荷已装变压器容量满足机械设备的用电要求。 选择二根VV-3×95＋2×50电缆为配电柜电源电缆。 选择总配电柜进线开关为HR5-400/3。 3．分路计算及电器选择 （1）塔式起重机回路

Ie=Pe/(1.732UeCosφ)=31.5/(1.732×0.38×0.85)=56.31 A 选择电缆为VV-5×16。

选择总柜分路开关及分配箱电电源开关为HR5-100。 选择总柜分路漏电保护器为DZ15L-100（100mA，≤0.2S）。

（2）施工升降机回路

Ie=Pe/(1.732UeCosφ)=15/(1.732×0.38×0.7)=32.5 A 选择电缆为VV-5×16。

选择总柜分路开关及分配箱电电源开关为HR5-100。 选择总柜分路漏电保护器为DZ15L-100（100mA，≤0.2S）。

（3）其它分路计算方法相同，计算书省略。