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(完整word版)新北师大版小学一年级下册数学期末试卷及答案

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choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: ... ... 一面…… ... 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer language plenary, and subject: application problem (1)--simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning--through examines the, find known conditions and by seeking problem 2, and analysis number relationship--analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation--lists formula, is out subdivisions 4, and test, and wrote answer--check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)--column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number三、1.20 2.小明 小兰 3.小明 四、 3 5 6 0 + 1 9 - 1 7 5 4 4 3 五、30√ 38√ □□六、② ③ ① 七、2.1 7

八、提示:图③与众不同。规律是:上面两个数的和等于下面的数。 九、1.提示:答案不唯一,只要上衣和裤子的总价不超过80元即可。 2.31+24+38 = 93(元) 十、30-17 = 13(个) 十一、1.28+11+59 = 98(人) 1.提示:能提出很多问题。

例如:① 游泳的比跳高的多多少人? 28-11 = 17(人) ② 跑步的和跳高的一共有多少人? 59+11 = 70(人)

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