{
break; }
for(int k = 0; k <= 20; k++) {
if((i + 2*j + 5*k) == 100) {
num++;
cout << \分\ << i << \个;\ << \分\ << j << \个;\ << \分\ << k << \个;\ << endl; }
if ((i + 2*j + 5*k) > 100) {
break; } }
} }
cout << num << endl; return 0; }
2.25 输入两个整数,按由小到大的顺序输出。要求使用变量的引用。 #include
a = a + b; b = a - b; a = a - b; }
int main() {
int a, b; cin >> a >>b; if(a > b) {
swap(a, b); }
cout << a << \ << b << endl; return 0; }
2.26 用二分法求解 f(x)=0的根。 #include
return 35*x +25; //假设f(x)=35x+25 }
int main() {
double a, b; cin >> a; if(Fun(a) == 0) {
cout << \ << a << endl; return 0; } do {
cin >> b; }
while ((Fun(a) * Fun(b)) >= 0); if(Fun(b) == 0) {
cout << \ << b << endl; return 0; }
if(a > b) {
a = a + b; b = a - b; a = a - b; } while(1) {
if(Fun((a + b)/2) == 0) {
cout << \ << (a + b)/2 << endl; return 0; }
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