1复数
?3?i的共轭复数是 (D) 2?i(A)2?i (B)2?i (C)?1?i (D)?1?i
1.(2012新课标文科2)复数z=
【命题意图】本题主要考查复数的除法运算与共轭复数的概念,是简单题.
?3?i=?1?i,∴z的共轭复数为?1?i,故选D. 2?i22.(2012新课标理科3)下面是关于复数z?的四个命题:其中的真命题为( C )
?1?i【解析】∵z=
p1:z?2 p2:z2?2i p3:z的共轭复数为1?i p4:z的虚部为?1
(A)p2,p3 (B) p1,p2 (C)p?,p? (D)p?,p?
【解析】选C z?22?(?1i)???1?i ?1?i(?1?i)?(?1i) p1:z?2,p2:z2?2i,p3:z的共轭复数为?1?i,p4:z的虚部为?1
1?2i?( B ) 2(1?i)1i 2 (C)1?
3.(2013新课标Ⅰ卷文科2)
(A)?1?1i 2
(B)?1?1i 2
(D)1?1i 2(D )
4. (2013新课标Ⅰ卷理科2)若复数z满足(3?4i)z?|4?3i|,则z的虚部为 A.?4 B.?4 5 C.4 D.
4 55.(2013新课标卷Ⅱ文科2)
2?(C) 1?i(C)
(D)1
(A)
(A)2 (B)2
6.(2013新课标卷Ⅱ理科2)设复数z满足(1?i)z?2i,则z?
(A)?1?i
(B)?1?i (C)1?i
(D)1?i
7.(2014新课标卷Ⅰ文科3)设z?1?i,则|z|?( B ) 1?iA.
123 B. C. D. 2 222【答案】:B
211?i11?1??1??i??i??i,z???????【解析】:z?,选B 1?i2222?2??2?22(1?i)38. (2014新课标卷Ⅰ理科2)=( D ) 2(1?i)A.1?i B.1?i C.?1?i D.?1?i
1?3i?( B ) 1?iA.1?2i B. ?1?2i C. 1?2i D. ?1?2i
(2)(2014新课标卷Ⅱ文科2)
9. (2014新课标卷Ⅱ理科2)设复数z1,z2在复平面内的对应点关于虚轴对称,z1?2?i,则z1z2?( A ) A. - 5
10.(2015新课标1卷文科3)已知复数z满足(z?1)i?1?i,则z?( C )
(A) ?2?i (B)?2?i (C)2?i (D)2?i
11.(2015新课标1卷理科1)设复数z满足
B. 5
C. - 4+ i
D. - 4 - i
1?z=i,则z= (A) 1?z(A)1 (B)2 (C)3 (D)2
12.(2015新课标II卷文科2)若a为实数,且
2?ai?3?i,则a?( D) 1?i A.?4 B. ?3 C. 3 D. 4
13.(2015新课标Ⅱ卷理科2)若a为实数且(2+ai)(a-2i)=-4i,则a=( B )
(A) ?1 (B) 0 (C) 1 (D) 2
相关推荐: