µÚÒ»·¶ÎÄÍø - רҵÎÄÕ·¶ÀýÎĵµ×ÊÁÏ·ÖÏíÆ½Ì¨

»¯Ñ鹤³õ¼¶¡¢Öм¶¡¢¸ß¼¶Ï°Ì⣨½ö¹©²Î¿¼£©[1][1]

À´Ô´£ºÓû§·ÖÏí ʱ¼ä£º2025/9/14 3:38:23 ±¾ÎÄÓÉloading ·ÖÏí ÏÂÔØÕâÆªÎĵµÊÖ»ú°æ
˵Ã÷£ºÎÄÕÂÄÚÈݽö¹©Ô¤ÀÀ£¬²¿·ÖÄÚÈÝ¿ÉÄܲ»È«£¬ÐèÒªÍêÕûÎĵµ»òÕßÐèÒª¸´ÖÆÄÚÈÝ£¬ÇëÏÂÔØwordºóʹÓá£ÏÂÔØwordÓÐÎÊÌâÇëÌí¼Ó΢ÐźÅ:xxxxxxx»òQQ£ºxxxxxx ´¦Àí£¨¾¡¿ÉÄܸøÄúÌṩÍêÕûÎĵµ£©£¬¸ÐлÄúµÄÖ§³ÖÓëÁ½⡣

²úÕß¡¢ÏúÊÛÕß ²éѯ£¬Ïò ²úÆ·ÖÊÁ¿¼à¶½²¿ÃÅ¡¢¹¤ÉÌÐÐÕþ¹ÜÀí²¿ÃÅ¡¢¼°ÓÐ¹Ø ²¿ÃŽøÐÐͶËß¡£

48¡¢ÒÔÉãÊ϶ȣ¨¡æ£©±íʾµÄζÈÓëÒÔ¿ª¶ûÎÄ£¨K£©±íʾµÄÈÈÁ¦Ñ§Î¶ÈÖ®¼äµÄÊýÖµ¹ØÏµÊ½Îª t/¡æ=T/K-273.15

49¡¢Ä³·ÖÎöÌìÆ½£¬ÔÚÒ»ÅÌÉϼÓ10mg±ê×¼íÀÂ룬ָÕëÆ«ÒÆ5·Ö¶È£¬Æä·Ö¶ÈÖµÊÇ£¨2£©mg¡£ 50¡¢Ôڲⶨ¸ÖÌúÖеÄÁ×ʱ£¬²»ÄÜÓÃH3PO4ÈܽâÊÔÑù£¬ÊÇÒòΪ£¨´ø½øÁ˱»²â×é·Ý£©¡£ 51¡¢ÓÃNaOHµÎ¶¨HClÈÜÒº£¬Æä¼ÆËãµÄÀíÂÛÒÀ¾ÝÊÇ£¨NaOHÎïÖʵÄÁ¿=HClÎïÖʵÄÁ¿£©¡£

£­1£­3£­7£­13£­1

52¡¢0.1molµÄijÈýÔªËᣬK1=1310£¬K2=2310£¬K3=3310£¬ÈôÓÃ0.1mol©qLµÄNaOH±êÒºµÎ¶¨£¬¿ÉµÃµ½£¨1£©¸öµÎ¶¨Í»Ô¾¡£

53¡¢ÈܼÁ¸ù¾ÝʹÓõģ¨ÈܼÁ£©²»Í¬£¬¿É·ÖΪËáÈÜ·¨ºÍ¼îÈÜ·¨¡£ 54¡¢ÖƱ¸ÊÔÑùÒ»°ã¿É·ÖÎªÆÆËé¡¢¹ýɸ¡¢»ìÔÈ¡¢£¨Ëõ·Ö£©Ëĸö²½Öè¡£

55¡¢ÍõË®µÄÈܽâÄÜÁ¦ºÜÇ¿£¬Ö÷ÒªÊÇÀûÓÃÁËHLlµÄÅäºÏÄÜÁ¦ºÍHNO3µÄ£¨Ñõ»¯ÄÜÁ¦£©¡£ 56¡¢µÎ¶¨¹ÜÔÚ×°±ê×¼ÈÜҺǰ£¬Ó¦ÏÈÓ㨴˱ê×¼ÈÜÒº£©ÁÜÏ´µÎ¶¨¹Ü2¡ª3´Î¡£ 57¡¢ÎïÖʵÄÁ¿µÄµ¥Î»Ãû³ÆÎª£¨Ä¦¶û£©¡£

58¡¢0.01mol/LµÄNaOHÈÜÒºPHֵΪ£¨12£©¡£ 59¡¢Ö¸Ê¾¼ÁÓë½ðÊôÀë×ÓÐγÉÅäºÏÎïµÄÎȶ¨ÐÔӦСÓÚEDTAÓë½ðÊôÀë×ÓÐγɵÄÅäºÏÎïµÄÎȶ¨ÐÔ£¬·ñÔò»á²úÉú£¨·â±ÕÏÖÏ󣩡£

60¡¢Óëµ¥Ò»µÄËá¼îָʾ¼ÁÏà±È£¬»ìºÏָʾ¼ÁÑÕÉ«±ä»¯£¨Ã÷ÏÔ£©£¬±äÉ«·¶Î§Õ­¡£ 61¡¢µ±ÈÜҺŨ¶ÈºÜϡʱ£¬¿ÉÓÃmg/L±íʾ£¬10mg/LÏ൱ÓÚ£¨10£©PPm¡£ 62¡¢0.1mol/LµÄNaOHºÍ0.2mol/LµÄ NaOHµÈÌå»ý»ìºÏºó£¨Ìå»ý¼Ó±¶£©ÈÜÒºµÄŨ¶È£¨6£©g/L¡£

63¡¢Ä¦¶ûÎüÊÕϵÊý±íʾÎïÖʶÔÄ³Ò»ÌØ¶¨²¨³¤µÄ£¨ÎüÊÕÄÜÁ¦£©¡£ 64¡¢Ïà¶Ô±ê׼ƫ²îÓֽбäÒìϵÊý£¬Æä¼ÆËãʽΪ£¨S/X£©3100%¡£ 65¡¢³£ÓÃŨH2SO4µÄÃܶÈΪ£¨1.84£©g/Ml¡£ 66¡¢NaHCO3µÄË×ÃûÊÇ£¨Ð¡ËÕ´ò£©¡£

67¡¢ÓÉÆó£¨Ê£©Òµ»òÆäÉϼ¶Óйػú¹¹Åú×¼·¢²¼µÄ±ê×¼³Æ£¨ÆóÒµ£©±ê×¼¡£ 68¡¢¸ù¾ÝȼÉÕÎïµÄÐÔÖÊ£¬¹ú¼ÊÉÏͳһ½«»ðÔÖ·ÖΪ£¨ËÄ£©Àà¡£

¶þ¡¢Ñ¡ÔñÌâ

1¡¢ÏÂÁÐÐðÊöµÄÖÜÆÚ±íÖÐͬ×åÔªËØµÄ¹ØÏµ£¬²»ÕýÈ·µÄÊÇ£¨A¡¢B £© A¡¢×î¸ßÕý¼Û±ØÈ»ÏàµÈ£» B¡¢×îÍâ²ãµç×ÓÊýÒ»¶¨ÏàµÈ£» C¡¢»¯Ñ§ÐÔÖÊÏàËÆ£» D¡¢½ðÊôÐÔ×ÔÉ϶øÏÂÔöÇ¿£» E¡¢ÒÔÉÏÐðÊöûÓв»ÕýÈ·µÄ

2¡¢ÏÂÁйÌ̬ÎïÖÊÄÜÐγɷÖ×Ó¾§ÌåµÄÊÇ£¨ C £©

A¡¢H2SO4£» B¡¢SiC£» C¡¢SiO2£» D¡¢KClO3£» E¡¢H2O

3¡¢ÓÐÒ»Á×ËáÑÎÈÜÒº£¬¿ÉÄÜÓÉNa3PO4¡¢Na2HPO4»òHaH2PO4»òÆäËü¶þÕßÖеĻìºÏÎï×é³É¡£½ñÒÔ°ÙÀï·Ó̪Ϊָʾ¼Á£¬ÓÃÑÎËá±ê×¼µÎ¶¨ÈÜÒºµÎ¶¨ÖÁÖÕµãʱÏûºÄV1mL£¬ÔÙ¼ÓÈë¼×»ùºìָʾ¼Á£¬¼ÌÐøÓÃÑÎËá±ê×¼µÎ¶¨ÈÜÒºµÎ¶¨ÖÁÖÕµãʱÓÖÏûºÄV2mL¡£µ±V2£¾V1£¬V1£¾0ʱ£¬ÈÜÒºµÄ×é³ÉΪ£¨ E £©

A¡¢Na2HPO4+ Na2HPO4£» B¡¢Na3PO4£»

C¡¢Na2HPO4£» D¡¢Na3PO4+HaH2PO4£»

µÚ 21 Ò³ ¹² 65 Ò³

E¡¢Na3PO4+ Na2HPO4£»

4¡¢µ±ÈõËᣨHA£©ºÍÈõËáÑÎ×é³ÉµÄ»º³åÈÜÒº×é·ÖŨ¶È±ÈΪÏÂÊöʱ£¬»º³åÈÝÁ¿×î´óµÄÊÇ£¨E£©

A¡¢HA£ºA¡ª=1£º9£» B¡¢HA£ºA¡ª=9£º1£» C¡¢HA£ºA¡ª=2£º1£» D¡¢HA£ºA¡ª=1£º2£» E¡¢HA£ºA¡ª=1£º1£»

5¡¢ÓÃÖØ¸õËá¼Ø·¨²â¶¨¿óʯÖÐÌúº¬Á¿Ê±£¬³£ÓÚÊÔÒºÖмÓÈëÁòÁ×»ìËᣬÆäÄ¿µÄÊÇ£¨C¡¢D¡¢E£©

A¡¢Ôö¼ÓÈÜÒºÖÐH+Àë×ÓµÄŨ¶È£» B¡¢Ðγɻº³åÈÜÒº£»

C¡¢Ê¹Fe3+Éú³ÉÎÞÉ«Îȶ¨µÄÅäºÏÎÓÐÀûÓÚÖÕµã¹Û²ì£»

D¡¢½µµÍFe3+/ Fe2+µç¶Ôµçѹ£¬Ôö´ó»¯Ñ§¼ÆÁ¿µã¸½½üµÄµçλͻԾ£¬Ê¹·´Ó¦¸üÍêÈ«£» E¡¢Ïû³ýFe3+µÄ»ÆÉ«£¬ÓÐÀûÓÚÖÕµãÑÕÉ«µÄ¹Û²ì¡£ 6¡¢ÏÂÁÐÄÜʹ³ÁµíÈܽâ¶È¼õСµÄÒòËØÓУ¨C£©

A¡¢ËáЧӦ£» B¡¢ÑÎЧӦ£» C¡¢Í¬Àë×ÓЧӦ£» D¡¢Ë®½âЧӦ£» E¡¢Éú³ÉÅäλ»¯ºÏÎï

7¡¢¾ßÓÐÏÂÁкÎÖÖ»îÐÔ»ùÍŵÄÊ÷֬ΪÑôÀë×Ó½»»»Ê÷Ö¬£¨ A¡¢B£©

?A¡¢R¡ªSO3H+£» B¡¢R¡ªCOOH£» ?C¡¢R¡ªN£¨CH3£©2£» D¡¢R¡ªNH3OH

¡ª E¡¢R¡ªNH£¨CH3£©?OH28¡¢ÔÚ×ÏÍâºÍ¿É¼û¹âÇøÓ÷ֹâ¹â¶È¼Æ²âÁ¿ÓÐÉ«ÈÜÒºµÄŨ¶ÈÏà¶Ô±ê׼ƫ²î×îСµÄÎü¹â¶ÈΪ£¨A£©

A¡¢0.434; B¡¢ 0.443; C¡¢ 0.343; D¡¢ 0.334 E¡¢0.234 9¡¢ÔÚµçλ·¨ÖÐΪָʾµç¼«£¬ÆäµçλӦÓë±»²âÀë×ÓµÄŨ¶È£¨D£© A¡¢Î޹أ» B¡¢³ÉÕý±È£» C¡¢µÄ¶ÔÊý³ÉÕý±È£» D¡¢·ûºÏÄÜË¹ÌØ¹«Ê½µÄ¹ØÏµ£» E¡¢·ûºÏÀ©É¢µçÁ÷¹«Ê½µÄ¹ØÏµ 10¡¢É«Æ×·ÖÎöÖУ¬Ê¹ÓÃÈȵ¼³Ø¼ì²âÆ÷ʱ£¬³£Ê¹ÓõÄÔØÆøÎª£¨ C£©

A¡¢µªÆø£» B¡¢ÑõÆø£» C¡¢ÇâÆø D¡¢ë²Æø£» E¡¢CO2Æø

11¡¢ÒÑÖªÔÚ·ÖÎöÌìÆ½ÉϳÆÁ¿Ê±ÓСÀ0.1mg£¬µÄÎó²î£¬µÎ¶¨¹Ü¶ÁÊýÓСÀ0.01mLµÄÎó²î£¬ÏÖ³Æ0.4237gÊÔÑù£¬¾­ÈܽâºóÓÃÈ¥21.18mL£¬Éè½ö¿¼ÂDzⶨ¹ý³ÌÖгÆÁ¿ºÍµÎ¶¨¹Ü¶ÁÊýÁ½ÏîÎó²î£¬Ôò·ÖÎö½á¹ûµÄ×î´óÏà¶ÔÎó²îÊÇ£¨B£©

A¡¢¡À0.0708% B¡¢¡À0.07% C¡¢¡À0.1461% D¡¢¡À0.14% E¡¢¡À0.1% 12¡¢ÔÚÆóÒµÖУ¨D£©ÊÇÖÊÁ¿µÄµÚÒ»ÔðÈÎÕß¡£

A¡¢Éú²ú¹¤ÈË£» B¡¢Ö÷¹ÜÖÊÁ¿²¿ÃŵĿơ¢´¦³¤£» C¡¢×ܹ¤³Ìʦ£» D¡¢³§£¨¿ó£©³¤¡¢¾­Àí E¡¢Ö÷¹ÜÖÊÁ¿µÄ¸±³§£¨¿ó£©³¤¡¢¸±¾­Àí

µÚ 22 Ò³ ¹² 65 Ò³

13¡¢ÏÂÁÐ˵·¨´íÎóµÄÊÇ£¨A¡¢B¡¢C¡¢D¡¢E£©

A¡¢²â¶¨ÇâÑõ»¯Äƺ¬Á¿Ê±¿ÉÓÃ0.1005mol/LµÄÁòËá±ê×¼µÎ¶¨ÈÜÒºµÎ¶¨£» B¡¢Ãܶȵĵ¥Î»·ûºÅΪkg2cm-3£» C¡¢ÊÒÎÂΪÉãÊÏ30¡æ

D¡¢Å¨ÁòËáµÄ±ÈÖØÎª1.84g/mL£»

E¡¢·¨¶¨¼ÆÁ¿µ¥Î»¹«²¼ºó£¬±ê×¼µÎ¶¨ÈÜÒºµÄŨ¶ÈÓ¦ÓÃĦ¶ûŨ¶ÈÀ´±íʾ 14¡¢Í¬ÎÂͬѹÏ£¬ÏàͬÖÊÁ¿µÄÏÂÁÐÆøÌ壬ÆäÖÐÌå»ý×îСµÄÊÇ£¨ A£© A¡¢Cl2£» B¡¢O2£» C¡¢NH3£» D¡¢H2£» E¡¢CO2

15¡¢ÓÃ0.01mol/LµÄNaOHÈÜÒºµÎ¶¨0.01mol/L HClÈÜҺʱ£¬×îºÏÊʵÄָʾ¼ÁÊÇ£¨ D£© A¡¢¼×»ùºì£¨pH=4.4~6.2£© B¡¢·Ó̪ £¨pH=8.2~10.00£© C¡¢¼×»ù³È£¨pH=3.1~3.4£© D¡¢Ëáºì £¨PH=6.4~8.2£© E¡¢°ÙÀï·Ó̪ £¨pH=8.3~10.5£©

16¡¢Ä³Èõ¼îMOHµÄKb=1310-5£¬ÔòÆä0.1mol/LË®ÈÜÒºµÄpHֵΪ£¨D£© A¡¢3.0£» B¡¢5.0£» C¡¢9.0£» D¡¢11.0£» E¡¢13.0 17¡¢¸ù¾Ýµç¼«µçλµÄ´óСÅжÏÏÂÁз´Ó¦ÄĸöÄܽøÐУ¿£¨B£©

¡ª+3??A¡¢AsO3+I+HOAsO+2I+2H£» ???2243¡ª+??B¡¢AsO3??AsO34+2I+2H?3+I2+H2O

18¡¢Óû²â¶¨Fe3+ºÍFe2+»ìºÏÒºÖÐFe3+º¬Á¿£¨ÒÑÖª×ÜFeº¬Á¿´óÓÚ100g/L£©¿ÉÓÃÏÂÁУ¨ A¡¢D £©·½·¨¡£

A¡¢¸ßÃÌËá¼Ø·¨£» B¡¢ÁÚ·ÆÔùßø·Ö¹â¹â¶È·¨£» C¡¢ÒøÁ¿·¨£» D¡¢ÖظõËá¼Ø·¨£» E¡¢³ÁµíµÎ¶¨·¨

19¡¢ÔÚº¬ÓÐCa2+¡¢Mg2+µÄ»ìºÏÒºÖУ¬»ìÓÐÉÙÁ¿Fe3+£¬ÓÃEDTA·¨²â¶¨Ca2+¡¢Mg2+º¬Á¿Ê±£¬ÒªÏû³ýFe3+µÄ¸ÉÈÅ£¬×îÓÐЧ¡¢×î¿É¿¿µÄ·½·¨ÊÇ£¨ C £©

A¡¢¼ÓÈëÑڱμÁ£» B¡¢¼ÓÈ뻹ԭ¼Á£» C¡¢³Áµí·ÖÀë·¨£» D¡¢Àë×Ó½»»»·¨£» E¡¢ÝÍÈ¡·ÖÀë·¨

20¡¢ÓÃͬһŨ¶ÈµÄKMnO4ÈÜÒº·Ö±ðµÎ¶¨ÈÝ»ýÏàµÈµÄFeSO4ºÍH2C2O4ÈÜÒº£¬ÏûºÄµÄKMnO4ÈÜÒºµÄÌå»ýÒ²ÏàµÈ£¬Ôò˵Ã÷Á½ÈÜÒºµÄŨ¶ÈcµÄ¹ØÏµÊÇ£¨ C £©

A¡¢c(FeSO4)=c(H2C2O4)£» B¡¢c(FeSO4)=2c(H2C2O4)£» C¡¢c(H2C2O4)=2c(FeSO4); D¡¢c(FeSO4)=4c(H2C2O4); E¡¢c(H2C2O4)=4c(FeSO4)

21¡¢ÏÂÁÐÓлúÎï²»ÄÜÓëË®»¥ÈܵÄÊÇ£¨ C¡¢E £©

A¡¢ÒÒË᣻ B¡¢ÒÒÈ©£» C¡¢ÒÒÃÑ£» D¡¢ÒÒ´¼£» E¡¢ÂÈÒÒÍé 22¡¢ÏõËáÓë¸ÊÓÍÔÚŨH2SO4´æÔÚÏÂÉú³ÉÏõËá¸ÊÓ͵ķ´Ó¦ÊÇ£¨ B £© A¡¢Ïõ»¯·´Ó¦£» B¡¢õ¥»¯·´Ó¦£» C¡¢»Ç»¯·´Ó¦£»

µÚ 23 Ò³ ¹² 65 Ò³

D¡¢¼Ó³É·´Ó¦£» E¡¢Ôí»¯·´Ó¦

23¡¢Ô­×ÓÎüÊÕ¹âÆ×ÊÇÓÉÏÂÁÐÄÄÖÖÁ£×Ó²úÉúµÄ£¿£¨ B £© A¡¢¹Ì̬ÎïÖÊÖÐÔ­×ÓµÄÍâ²ãµç×Ó£» B¡¢ÆøÌ¬ÎïÖÊÖлù̬ԭ×ÓµÄÍâ²ãµç×Ó£» C¡¢ÆøÌ¬ÎïÖÊÖм¤·¢Ì¬Ô­×ÓµÄÍâ²ãµç×Ó£» D¡¢ÒºÌ¬ÎïÖÊÖÐÔ­×ÓµÄÍâ²ãµç×Ó£» E¡¢ÆøÌ¬ÎïÖÊÖлù̬ԭ×ÓµÄÄÚ²ãµç×Ó 24¡¢ÎªÏÂÁеçλµÎ¶¨Ñ¡ÔñºÏÊʵÄָʾµç¼«£» £¨1£©Ñõ»¯»¹Ô­µÎ¶¨£¨ A £©£»£¨2£©ÅäλµÎ¶¨£¨ E £© £¨3£©³ÁµíµÎ¶¨£¨ÒøÁ¿·¨µÎ¶¨Â±Àë×Ó£©£¨ B¡¢C £© A¡¢²¬µç¼«£» B¡¢Òøµç¼«£» C¡¢Ag-AgSµç¼«£» D¡¢²£Á§µç¼«£» E¡¢Hg/Hg-EDTAµç¼¶

25¡¢ÔÚÏÂÊöÇé¿öϺÎÕ߶Բⶨ½á¹û²úÉúÕýÎó²î£¨ A¡¢C £© A¡¢ÓÃÖ±½Ó·¨ÒÔÑÎËá±ê×¼µÎ¶¨ÈÜÒºµÎ¶¨Ä³¼îÑùʱÈÜÒº¹Ò±Ú£»

B¡¢ÒÔK2Cr2O7Ϊ»ù×¼ÎïÓõâÁ¿·¨±ê¶¨Na2S2O3ÈÜÒº£¬µÎ¶¨Ëٶȹý¿ì£¬²¢¹ýÔç¶ÁÊý£» C¡¢ÓÃÓڱ궨±ê×¼µÎ¶¨ÈÜÒºµÄ»ù×¼Îï³ÆÁ¿Ê±Îü³±ÁË£¨Ö±½ÓµÎ¶¨·¨£©£» D¡¢ÒÔEDTA±ê×¼µÎ¶¨ÈÜÒº²â¶¨Ca¡¢Mgº¬Á¿Ê±£¬µÎ¶¨Ëٶȹý¿ì£» E¡¢ÒÔʧȥ²¿·Ö½á¾§Ë®µÄÅðɰΪ»ùÉÁÎï±ê¶¨ÑÎËáÈÜÒºµÄŨ¶È¡£ 26¡¢Óк¦ÆøÌåÔÚ³µ¼ä´óÁ¿ÒÝɢʱ£¬·ÖÎöÔ±ÕýÈ·µÄ×ö·¨ÊÇ£¨ C¡¢D £© A¡¢´ôÔÚ·¿¼äÀï²»³öÈ¥£»

B¡¢ÓÃʪë½íÎæ×¡¿Ú±Ç¡¢Ë³·çÏòÅܳö³µ¼ä£» C¡¢ÓÃʪë½íÎæ×¡¿Ú±ÇÄæ·çÅܳö³µ¼ä£» D¡¢´ø·À¶¾Ãæ¾ßÅܳö³µ¼ä£»

E¡¢²éÕÒ¶¾ÆøÐ¹Â©À´Ô´£¬¹Ø±ÕÓйط§ÃÅ

27¡¢²ÉÓÃÖ±½ÓµÎ¶¨·¨£¬ÈôÔڵζ¨Ç°Î´½«Ðü¹ÒÔڵζ¨¹Ü¼â¶ËµÄÒºµÎ¿¿È¥£¬Ôò»áÒýÆð½á¹û£¨B£©¡£

A¡¢Æ«Àë B¡¢Æ«µÍ C¡¢²»±ä 28¡¢ÄÜÓÃÓÚÒøÁ¿·¨²â¶¨µÄָʾ¼ÁÊÇ£¨D£©¡£

A¡¢¸õºÚ B¡¢¸ßÃÌËá¼Ø C¡¢ÖظõËá¼Ø D¡¢Ìúï§·¯ 29¡¢ÊôÓÚÓÀ¾ÃÓ²¶ÈµÄÊÇ£¨D£©¡£

A¡¢Ca£¨HCO3£© B¡¢Mg£¨CO3£© C¡¢MgLO3 D¡¢MgCl2 30¡¢²»ÄÜ×÷Ϊ»ù×¼ÎïÖʵÄÊÇ£¨B£©¡£

A¡¢ÁÚ±½¶þ¼×ËáÇâ¼Ø B¡¢Ì¼ËáÇâÄÆ C¡¢Ì¼Ëá¸Æ D¡¢Ð¿ 31¡¢ÓÃÎÞË®Na2CO3×÷ÈÛ¼Áʱ²»ÄÜÑ¡Óã¨A£©ÛáÛö¡£ A¡¢Ê¯Ó¢ B¡¢²¬ C¡¢Ìú D¡¢Äø 32¡¢ÎïÖʵÄÁ¿Å¨¶Èµ¥Î»Îª£¨B£©¡£

3

A¡¢g/L B¡¢mol/m C¡¢Kg/m3 D¡¢m3/mol

33¡¢·´Ó¦Aa+Bb=mc+Nd£¬Èô½µµÍCÎïÖÊŨ¶È£¬DŨ¶È»á£¨A£©¡£

µÚ 24 Ò³ ¹² 65 Ò³

»¯Ñ鹤³õ¼¶¡¢Öм¶¡¢¸ß¼¶Ï°Ì⣨½ö¹©²Î¿¼£©[1][1].doc ½«±¾ÎĵÄWordÎĵµÏÂÔØµ½µçÄÔ£¬·½±ã¸´ÖÆ¡¢±à¼­¡¢ÊղغʹòÓ¡
±¾ÎÄÁ´½Ó£ºhttps://www.diyifanwen.net/c4pznp0sgtt77xpo57wv5_6.html£¨×ªÔØÇë×¢Ã÷ÎÄÕÂÀ´Ô´£©

Ïà¹ØÍÆ¼ö£º

ÈÈÃÅÍÆ¼ö
Copyright © 2012-2023 µÚÒ»·¶ÎÄÍø °æÈ¨ËùÓÐ ÃâÔðÉùÃ÷ | ÁªÏµÎÒÃÇ
ÉùÃ÷ :±¾ÍøÕ¾×ðÖØ²¢±£»¤ÖªÊ¶²úȨ£¬¸ù¾Ý¡¶ÐÅÏ¢ÍøÂç´«²¥È¨±£»¤ÌõÀý¡·£¬Èç¹ûÎÒÃÇ×ªÔØµÄ×÷Æ·ÇÖ·¸ÁËÄúµÄȨÀû,ÇëÔÚÒ»¸öÔÂÄÚ֪ͨÎÒÃÇ£¬ÎÒÃǻἰʱɾ³ý¡£
¿Í·þQQ£ºxxxxxx ÓÊÏ䣺xxxxxx@qq.com
ÓåICP±¸2023013149ºÅ
Top