得直线l的极坐标方程为???(??R). 由曲线C2的极坐标方程??2sin?, 得直角坐标方程为x?(y?1)?1,
22?x?cos?C∴曲线2的参数方程为?(?为参数).
y?1?sin??(2)当??当???6时,直线l的极坐标方程为???6(??R).
?6时,OA?4cos?6?23,OB?2sin?6?1,
∴AB?OA?OB?23?1.
??23.解:(1)∵x?a?x???a由题意,得a?bc23bcbc??(当且仅当(x?a)?x????0时取等号), 2323??bc??7. 232222?2?1?2?1?2??bc?根据柯西不等式,可知(a?b?c)?1?????????a????49,
23??2??3??????∴a?b?c?36. ∴a?b?c的最小值为36.
222222a4b4c4222222(2)∵2?b?2a,2?c?2b,2?a?2c,
bcaa4b4c4222222∴2?2?2?a?b?c?2(a?b?c), bcaa4b4c4222∴2?2?2?a?b?c. bca 11
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