车床主轴设计材料力学课程设计 - 图文

ω1=32.09 ω2=118.23 ω3=80.72 ω4=127.85 ω5=5.20

Mc1=0.028 Mc2=0.081 Mc3=0.100 Mc4=0.060 Mc5=0.020

fEz??i?15?iMciEI?116.75?1Mc1??2Mc2??3Mc3??4Mc4??5Mc5?EIEI

??fE?22fEy?fEz?34.54??fE??3.5?10?4mEI

D3?5.97?10?2m

3. 根据C点的刚度对轴校核：在C点分别加一绕Y、Z方向的单位偶有弯矩图如下：

２１

ω1=3.40 ω2=0.18 ω3=187.7 ω4=47.03 ω5=176.65 Mc1=Mc2=Mc3=Mc4=Mc5=1.00

?Cy??i?15?iMciEI?407.801??1Mc1??2Mc2??3Mc3??4Mc4??5Mc5?EI EI??２２

ω1=32.09 ω2=118.03 ω3=80.72 ω4=127.85 ω5=5.20 Mc1=Mc2=Mc3=Mc4=Mc5=1.00

?Cz??i?15?iMciEI??1363.89?1Mc1??2Mc2??3Mc3??4Mc4??5Mc5??EIEI

??22?C??Cy??Cz?546.55?[?C]?0.0028EI

解得:D4?7.08?10?2m

综上所述:D?max?D1,D2,D3,D4??8.18?10?2m

3）疲劳强度校核：

２３

查材力课设附录知?b?598Mp

由教材图13-10 a)查得K??1.72 由教材图13-10 b)查得K??1.52

由教材图13-12 查得 ???0.73 ???0.72

由表13?3用插入法得??1.98 W??D332(1??4)?4.08?10?5m3；

?Mmaxmax???min?W?1899.834.08?10?5?46.56MPa ?MXmax?W?131.3016?10?5?1.61MPa P8.n??1??K?420?106?72??1.?7.58；

max??0.73?1.98?46.56?106n??1??K?240?106?1.52?139.81；

?max?1.61????0.72?1.98106n?n?n?58?139.81n22?7.??n?7.582?139.812?7.57?3；

故满足强度条件。

２４