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I1?IR1R2 同理:I2?I
R1?R2R1?R2Ur(s)11 其中:Z??1/Cs?//Z1 Z1?R1??R1Cs?1?代入Z?Z?R2CsCSI(s)?11?R1Cs?1?1RCs?11中,则Z?CsCs ?11CsR1Cs?2??R1Cs?1?CsCs11Cs I1(s)?I(s)?I(s)11R1Cs?2?R1?CsCsU(s)111Ur(s)Uc(s)?I1(s)?I(s)R2?r?R2CsZ?R2R1Cs?2CsZ?R2?Ur(s)Ur(s)11?R21R1Cs?1R1Cs?2Cs1R1Cs?1?R2?R2CsR1Cs?2CsR1Cs?2
?所以:
Ur(s)Ur(s)?R1Cs?2?Cs?R2R1Cs?1?R2?R1Cs?2?CsR1Cs?1?R2?R1Cs?2?CsUc(s)R2?R1Cs?2?Cs1??Ur(s)R1Cs?1?R2?R1Cs?2?CsR1Cs?1?R2?R1Cs?2?CsR1R2C2s2?2R2Cs?1?R1R2C2s2?R1Cs?2R2Cs?1解法2:首先将上图转换为复阻抗图(如解法1图)
I1(s)?Ur(s)?Uc(s)
R11??I2(s)?I1(s)?R1??Cs?I1(s)?R1Cs?1?
Cs??I(s)?I1(s)?I2(s)
Uc(s)?I1(s)1?I(s)R2 Cs画出其结构图如下:
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1 Cs Ur(s) - 1 I1 R1 R1Cs+1 I2 I Uc(s) R2
化简上面的结构图如下: 1 Cs Ur(s) - 1 I1 R1 R1Cs+2 I Uc(s) R2
应用梅逊增益公式:
Uc(s)1n??Tk?k
Ur(s)?k?1其中:??1?La?Lb
La??R2?R1Cs?2?、Lb??1 R1R1CsR2?R1Cs?2??1?R1Cs?R2Cs?R1Cs?2??1 R1R1CsR1Cs所以??1?T1?R2?R1Cs?2?、?1?1 R11、?2?1 R1CsT2?所以:
R2?R1Cs?2??1Uc(s)R1R1CsR2Cs?R1Cs?2??1??Ur(s)R1Cs?R2Cs?R1Cs?2??1R1Cs?R2Cs?R1Cs?2??1R1CsR1R2C2s2?2R2Cs?1?R1R2C2s2?R1Cs?2R2Cs?1解:(c) 解法与(b)相同,只是参数不同。
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2-14 试求出图P2-2中各有源网络的传递函数W(s)=Uc(s)/Ur(s)。 C0 uc R0 (a) R1 C1 R1 C1 ur R0 (b) R1 C1 R2 C2 ur R0 uc uc (c) 解:(a)
Uc(s)Z??1Ur(s)Z0 其中:
Z1?R1?11?R1C1s?1??1?T1s?1? ?C1sC1sC1s1C0sR0R01Z0?//R0??? 其中:T1?R1C1、T0?R0C0
1C0sR0C0s?1T0s?1R0?C0sR0所以:
Uc(s)1?T0s?1??T1s?1? ??Ur(s)R0C1s R1 C1 C0 uc R0 (a) 解:(b)如图:
R1 C1 R3 I1 R2 ur I0 uc R0 (b) 将滑动电阻分为R2和R3,
I0?I1 IR30?Ur(s)R,
Ic(s)1??U,其0ZR13?R1?C1sR11Z?RC1sR1R?R1C1s?1??R12??RR12?R?2s?1
1?1C1s?1R1C1C1sZ??R?1??所以:
Uc(s)R3R1?3??C1s??C1s?1?U??R????R1?R3?r(s)0RR22?R2?R1C1s?1??R1?0R13C1s解:(c)解法与(b)相同。
2-15 求图P2-3所示各机械运动系统的传递函数。 (1)求图(a)的
Xc(s)?? (2)求图(b)的Xc(s)X??
r(s)Xr(s)(3)求图(c)的X2(s)X?? (4)求图(c)的 1(s)
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中
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