标准C语言程序设计第五版课后练习题答案(完整资料).doc

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课后练习题答案 Chapter 1 1.1 ×√×√√×√××√ 1.2 b c 1.3 ad 1.4 semicolon printf math.h \\n Chapter 2

2.1 ×√××√√×√××√× 2.2 typedef 255 external const Chapter 3

3.1 ×√××√√×××√√√

3.2 integer modula 6 logical sizeof paratheses typeconversion precedence 3.3 F F T F F F 3.4 F T T T F 3.5 (b) (c)

3.6 0 -2 7 10.25 false 3 3 1 3.10 0 1 1 1 1 3.11 d } 100 3.12 110 111 3.13 1 3.14 200 3.15 x<=y 3.16 TRUE 3.19 2 1 4

3.20 -40 40

Chapter 4

4.1 ×√√√√√××√√√×

4.2 %hd %x ctype.h %l %*d [^] blank 6 - %e

4.4 (a) scanf(“%d %c %d”, &a, &b, &c); (b)scanf(“%d %f %s”, &a, &b, &c);

(c) scanf(“%d-%d-%d”, &a, &b, &c); (d) scanf(“%d %s %d”, &a, &b, &c);

4.5 (a)10x1.230000 (b)1234x 1.23 (c)1234 456.000000 (d) “123.40 ” (e) 1020 1222(乱码)

4.7 （a）1988 x (b)乱码 （c）120 乱码 （d）乱码 x 4.8 （a）1275 -235.740000 (b) 1275 -235.740000 (c) 0 0.000000

(d) 1275xxxx-235.74 (e)Cambridge

(f)1275 Cambridge 4.10 1988 无 无 Chapter 5

5.1 √×√××××××√ 5.2 && switch break if-else x=y

5.4 （a）x = 2; y = 0; (b) x = 1; y = 0; 5.5 (a) if (grade <= 59) if (grade >= 50)

second = second + 1;

(b) if (number > 100) printf(“out of range”); else if (number < 0) printf(“out of range”); else sum = sum + number; (c)

if (T > 200) printf(“admitted”); else if (M > 60)

{if (M > 60) printf(“admitted”);} else printf(“not admitted”); 5.6 F T F T

5.8 (a) x > 10 (b) (x != 10)||(y ! = 5) || (z >= 0)

(c) (x + y != z) || (z > 5) (d) (x > 5) || (y != 10) || (z >= 5) 5.9 (a) x = 5; y = 10; z = 1 (b) x = 5; y = 10; z = 1 (c) x = 5; y = 0; z =0 (d) 无变化

5.10 （a） x= 0; y = 2; z = 0; (b) x = 1; y = 2; z = 0; 5.12 8

5.13 Delhi Bangalore END 5.14 2 4 4 8

5.15 0 0 2 5.16 25

5.17 Number is negative 5.18 ABC 5.19 10

5.20 无输出 Chapter 6

6.1 √√√××√×√√×

6.2 n continue infinite indefinite-repetition-loop counter-variable 6.9 （a） 43210 (b)4321 (c)55555…55555(d)10 8

6.11 （a）无数次 x = 10; x = 5; x = 10; x = 5; x = 10;… (b)5次 m = 3, m = 5, m = 7, m = 9, m = 11 (c)无数次, i 恒为0

(d)4次 m = 11 n = 9; m = 12 n = 11; m = 13, n = 13; m = 14, n = 15; 6.13

（a）for (n = 1; n <= 32; n = n * 2) printf(\（b）for (n = 1; n <= 243; n = n * 3) printf(\（c）for (n = -4; n <= 4; n = n + 2) printf(\(d) sum = 0;

for (i = 2; i <= 16; i = sum) {

sum = sum + i; n = n - i;

printf(\ }

6.16 100 90 80 70 60 50 40 30 20 10 0

6.17 m = 20时陷入死循环， 程序无输出 6.18 1 6.19 1

6.20 死循环，延长时间用 Chapter 7

7.1 √×√××√√√√××√

7.2 index/subscript run-time dynamic multi-dimensional sorting 7.14 15

7.15 HLOWRD Chapter 8

8.1 ×√√√×√××√×××√×√

8.2 %[ a-z,A-Z] strcpy 3 stdlib gets strlen strstr strcmp s1-s2 puts 8.6 (a) The sky is the limit.

(b) The sky is (c) T

(d) The sky is the limit (e)84 104 101 32 115 107 121 32 105 115 32

116 104 101 32 108 105 109 105 116

(f)输出1 2 3 4 5 6 7 8 9…21这些ASCII码对应的字符，无显示符号 (g)% (h)U 8.7 (d) 8.8 7

8.9 (a)he(b)heorshe(c)5 7 8.11 pune Chapter 9

9.1 √×××√×××√√√×××√×√√××

9.2 actual-parameter local-variable int data-type variable-name scope recursive static type auto 9.8 abceg 9.9 abcdeg

9.12 (a) 5 (b) 4 (c)3 (d)0

9.13 (a) 5 4 4 0 (b) 5.0 4.0 3.0 0.67

9.14 题目错，设z = 5；结果为：200 1000 9.15 100

9.16 x = 3; y = 0 Chapter 10

10.1 ×√√√√×√√×√√√××√

10.2 typedef union tag_name pointer member Chapter 11

11.1 √×√√√√×√×× 11.2 address * * 0 null