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(3)PC?6,
5106PNPA8,∴PN?,∴NC:PC?5:9,所求距离h?. ?927PAPC323.(1)P3?p3?3p2(1?p)?p2(3?2p),P4?p4?4p3(1?p)?p3(4?3p); (2)① P1?P3且P1?P4,∴0?p?11;② P?p?1; 3?P1且P3?P4,2211时,恰做一道及格概率最大;p?时,P1?P3;22③ P4?P无解;综上,0?p?4?P3,1且P1?p?1时,恰做三道及格概率最大. 2
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