CO2+NaOH === NaHCO3
因NaHCO3溶液和Na2CO3溶液均呈碱性,则溶液中的溶质可能是Na2CO3或NaHCO3.
(2)由AB段产生气体可知发生反应的离子方程式为:HCO +H+ === CO2↑+H2O,此段消耗的n(H+)=1 mol/L ×0.1 L=0.1 mol,故溶液中n(CO )=n(HCO )=0.1 mol. ①OA段CO 消耗0.1 mol H+,OH-消耗0.1 mol H+. ③ V(CO2)=0.1 mol×22.4 L/mol=2.24 L 答案:(1)Na2CO3或NaHCO3
(2)①H++OH- === H2O;CO +H+ === HCO ②2240
相关推荐: