电力系统不对称故障分析与计算

Y2=(double)1\\2*b*L*(Uav*Uav)/100; Printf(“\\n3:”);

Scanf(“%f,%f,”,&X,b,&&L); X7= X*L*Sn/(Uav*Uav);

Y3=(double)1\\2*b*L*(Uav*Uav)/100;

Printf(“X5=%f,X6=%f,X7=%f\\n”,X5,X6,X7); Printf(“Y1=%f,Y2=%f,Y3=%f\\n”,Y1,Y2,Y3); Printf(“Y1=Y1,Y2=Y2,Y3=Y3\\n”,Y1,Y2,Y3);

Printf(“please input the K(7) to see Y array: \\n”); Scanf(“&d”,&K);

For(n=0;n

Y[0][0]=1/X1+1/X2; Y[0][1]=-1/(X2*K1); Y[1][0]= Y[0][1];

Y[1][1]=1/X5+Y1+1/(X2*K1*K1); Y[1][2]=-1/X5; Y[2][1]= Y[1][2];

Y[2][2]=Y1+1/X5+Y2+1/X7+(1/2*X3*K2*K2); Y[2][3]=-1/(1/2*X3*K2);

Y[2][4]=-1/X6; Y[2][5]=-1/X7; Y[3][2]= Y[2][3];

Y[3][3]=1/(1/2*X3)+(1/2*X10); Y[4][2]= Y[2][4]; Y[4][4]=Y2+1/X8 +1/X6; Y[5][5]=Y3+1/X7+1/(X4*K3*K3); Y[5][6]=-1/(X4*K3); Y[6][5]= Y[5][6]; Y[6][6]= 1/X4; For(n=0;n

{ Printf(“j%,2f\\t”,Y[n][j]); If(j==6) Printf(“\\n”)}

For(n=0;n

Printf(“please input the number of short cuicit:K=I(i<7)\\n”); Scanf(“&f”,&d); U[d]=1; I[0]=0.0;

For(n=0;n

Printf(“I[0]=%f\\n”,I[n++]); Printf(“I[1]=%f\\n”,I[n++]); Printf(“I[2]=%f\\n”,I[n++]); Printf(“I[3]=%f\\n”,I[n++]); Printf(“I[4]=%f\\n”,I[n++]); Printf(“I[5]=%f\\n”,I[n++]); Printf(“I[6]=%f\\n”,I[n++]);

IK=I[d]*Sn/(sqrt(3)*Uav); IM=2.55*IK; SK=1.732*IK*Uav;

Printf(“IK=%f,Sd=%f,IM=%f”,IK,Sd,IM);

Printf(“please input the K(7) to see Y array: \\n”); Scanf(“&d”,&K); 负序导纳矩阵 For(n=0;n

Y[0][0]=1/X1+1/X2;

Y[0][1]=-1/(X2*K1); Y[1][0]= Y[0][1];

Y[1][1]=1/X5+Y1+1/(X2*K1*K1); Y[1][2]=-1/X5; Y[2][1]= Y[1][2];

Y[2][2]=Y1+1/X5+Y2+1/X7+(1/2*X3*K2*K2); Y[2][3]=-1/(1/2*X3*K2); Y[2][4]=-1/X6; Y[2][5]=-1/X7; Y[3][2]= Y[2][3];

Y[3][3]=1/(1/2*X3)+(1/2*X10); Y[4][2]= Y[2][4]; Y[4][4]=Y2+1/X8 +1/X6; Y[5][5]=Y3+1/X7+1/(X4*K3*K3); Y[5][6]=-1/(X4*K3); Y[6][5]= Y[5][6]; Y[6][6]= 1/X4; For(n=0;n

{ Printf(“j%,2f\\t”,Y[n][j]); If(j==6)