= 3(1- e?2t)A t≥0
∴ i (t) = i L(t) -i C(t) = 3(1- e?2t)+3e?t A t≥0 七.解:画出相量模型 ,可得:
&U100?0?S??52??45?A
I&?5?j15?10?(?j10)10?j1010?j10 I&1?I&1010?j10?52??45??12??45??5?0?A I&2?I&?I&1?5?j5?5??j5?5??90?A
∴ i(t) = 10 cos ( 10 t - 45°)A
i1(t) = 52 cos 10 t A
i2(t) = 52cos ( 10 t - 90°)A
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